2c^2-23c+11=0

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Solution for 2c^2-23c+11=0 equation:


Simplifying
2c2 + -23c + 11 = 0

Reorder the terms:
11 + -23c + 2c2 = 0

Solving
11 + -23c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -2c)(11 + -1c) = 0

Subproblem 1

Set the factor '(1 + -2c)' equal to zero and attempt to solve: Simplifying 1 + -2c = 0 Solving 1 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2c = 0 + -1 -2c = 0 + -1 Combine like terms: 0 + -1 = -1 -2c = -1 Divide each side by '-2'. c = 0.5 Simplifying c = 0.5

Subproblem 2

Set the factor '(11 + -1c)' equal to zero and attempt to solve: Simplifying 11 + -1c = 0 Solving 11 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + -1c = 0 + -11 Combine like terms: 11 + -11 = 0 0 + -1c = 0 + -11 -1c = 0 + -11 Combine like terms: 0 + -11 = -11 -1c = -11 Divide each side by '-1'. c = 11 Simplifying c = 11

Solution

c = {0.5, 11}

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